Complex Sql Queries Interview Questions and Answers - Advanced SQL Queries - LearnHowToCode SarkariResult.com Interview Questions and Answers LearnHowToCodeOnline
Complex Sql Queries Interview Questions and Answers - Advanced SQL Queries

Complex Sql Queries Interview Questions and Answers - Advanced SQL Queries

50) Display the name of the employee who earns highest salary.

SQL>select ename from emp where sal=(select max(sal) from emp);

51) Display the employee number and name for employee working as clerk and earning highest salary among clerks.

SQL>select empno,ename from emp where where job='CLERK' and sal=(select max(sal) from emp  where job='CLERK');

52) Display the names of salesman who earns a salary more than the highest salary of any clerk.

SQL>select ename,sal from emp where job='SALESMAN' and sal>(select max(sal) from emp where job='CLERK');

53) Display the names of clerks who earn a salary more than the lowest salary of any salesman.

SQL>select ename from emp where job='CLERK' and sal>(select min(sal) from emp where job='SALESMAN');

54)Display the names of employees who earn a salary more than that of Jones or that of salary grether than   that of scott.

SQL>select ename,sal from emp where sal>(select sal from emp where ename='JONES')and sal> (select sal from emp
where ename='SCOTT');

55) Display the names of the employees who earn highest salary in their respective departments.

SQL>select ename,sal,deptno from emp where sal in(select max(sal) from emp group by deptno);

56) Display the names of the employees who earn highest salaries in their respective job groups.

SQL>select ename,sal,job from emp where sal in(select max(sal) from emp group by job)

57) Display the employee names who are working in accounting department.

SQL>select ename from emp where deptno=(select deptno from dept where dname='ACCOUNTING')

58) Display the employee names who are working in Chicago.

SQL>select ename from emp where deptno=(select deptno from dept where LOC='CHICAGO')

59) Display the Job groups having total salary greater than the maximum salary for managers.

SQL>SELECT JOB,SUM(SAL) FROM EMP GROUP BY JOB HAVING SUM(SAL)>(SELECT MAX(SAL) FROM EMP WHERE JOB='MANAGER');

60) Display the names of employees from department number 10 with salary greater than that of any employee working in other department.

SQL>select ename from emp where deptno=10 and sal>any(select sal from emp where deptno not in 10).

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61) Display the names of the employees from department number 10 with salary greater than that of all employee working in other departments.

SQL>select ename from emp where deptno=10 and sal>all(select sal from emp where deptno not in 10).

62) Display the names of the employees in Uppercase.

SQL>select upper(ename)from emp

63) Display the names of the employees in Lowercase.

SQL>select lower(ename)from emp

64) Display the names of the employees in Propercase.

SQL>select initcap(ename)from emp;

65) Display the length of Your name using appropriate function.

SQL>select length('name') from dual

66) Display the length of all the employee names.

SQL>select length(ename) from emp;

67) select name of the employee concatenate with employee number.

SQL>select ename||empno from emp;

68) User appropriate function and extract 3 characters starting from 2 characters from the following  string 'Oracle'. i.e the out put should be 'ac'.

SQL>select substr('oracle',3,2) from dual

69) Find the First occurance of character 'a' from the following string i.e 'Computer Maintenance Corporation'.

SQL>SELECT INSTR('Computer Maintenance Corporation','a',1) FROM DUAL

70) Replace every occurrence of alphabet A with B in the string Allens(use translate function)

SQL>select translate('Allens','A','B') from dual

71) Display the information from emp table.Where job manager is found it should be displayed as boos(Use replace function).

SQL>select replace(JOB,'MANAGER','BOSS') FROM EMP;

72) Display empno,ename,deptno from emp table.Instead of display department numbers[B1]  display the related department name(Use decode function).

SQL>select empno,ename,decode(deptno,10,'ACCOUNTING',20,'RESEARCH',30,'SALES',40,'OPRATIONS') from emp;

73) Display your age in days.

SQL>select to_date(sysdate)-to_date('10-sep-77')from dual

74) Display your age in months.

SQL>select months_between(sysdate,'10-sep-77') from dual

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75) Display the current date as 15th Augest Friday Nineteen Ninety Saven.

SQL>select to_char(sysdate,'ddth Month day year') from dual

76) Display the following output for each row from emp table.scott has joined the company on wednesday 13th August ninten nintey.

SQL>select ENAME||' HAS JOINED THE COMPANY ON  '||to_char(HIREDATE,'day ddth Month  year')   from EMP;

77) Find the date for nearest saturday after current date.

SQL>SELECT NEXT_DAY(SYSDATE,'SATURDAY')FROM DUAL;

78) Display current time.

SQL>select to_char(sysdate,'hh:MM:ss') from dual.

79) Display the date three months Before the current date.

SQL>select add_months(sysdate,3) from dual;

80) Display the common jobs from department number 10 and 20.

SQL>select job from emp where deptno=10 and job in(select job from emp where deptno=20);

81) Display the jobs found in department 10 and 20 Eliminate duplicate jobs.

SQL>select distinct(job) from emp where deptno=10 or deptno=20;
          (or)
SQL>select distinct(job) from emp where deptno in(10,20);

82) Display the jobs which are unique to department 10.

SQL>select distinct(job) from emp where deptno=10

83) Display the details of those who do not have any person working under them.

SQL>select e.ename from emp,emp e where emp.mgr=e.empno group by e.ename having count(*)=1;

84) Display the details of those employees who are in sales department and grade is 3.

SQL>select * from emp where deptno=(select deptno from dept where dname='SALES')and sal between(select losal from salgrade where grade=3) and (select hisal from salgrade where grade=3);

85) Display those who are not managers and who are managers any one.
i)display the managers names

SQL>select distinct(m.ename) from emp e,emp m where m.empno=e.mgr;

 ii)display the who are not managers

SQL>select ename from emp where ename not in(select distinct(m.ename) from emp e,emp m where m.empno=e.mgr);

86) Display those employee whose name contains not less than 4 characters.

SQL>select ename from emp where length(ename)>4;

87) Display those department whose name start with "S" while the location name ends with "K".

SQL>select dname from dept where dname like 'S%' and loc like '%K';

88) Display those employees whose manager name is JONES.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and e.ename='JONES';

89) Display those employees whose salary is more than 3000 after giving 20% increment.

SQL>select ename,sal from emp where (sal+sal*.2)>3000;

90) Display all employees while their dept names;

SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno

91) Display ename who are working in sales dept.

SQL>select ename from emp where deptno=(select deptno from dept where dname='SALES');

92) Display employee name,deptname,salary and comm for those sal in between 2000 to 5000 while location is chicago.

SQL>select ename,dname,sal,comm from emp,dept where sal  between 2000 and 5000 and loc='CHICAGO' and emp.deptno=dept.deptno;

93) Display those employees whose salary greter than his manager salary.

SQL>select p.ename from EMP e, EMP p where e.empno=p.mgr and p.sal>e.sal

94) Display those employees who are working in the same dept where his manager is work.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.deptno=e.deptno;

95) Display those employees who are not working under any manager.

SQL>select ename from emp where mgr is null

96) Display grade and employees name for the dept no 10 or 30 but grade is not 4 while joined the company before 31-dec-82.

SQL>select ename, grade from EMP, salgrade where Sal between losal and Hisal and deptno     in (10, 30) and grade<>4 and hiredate<'31-DEC-82';

97) Update the salary of each employee by 10% increments that are not Eligible for commission.

SQL>update emp set sal=sal+sal*10/100 where comm is null;

98) SELECT that employee who joined the company before 31-dec-82 while Their dept location is new york or Chicago.

SQL> SELECT EMPNO, ENAME, HIREDATE, DNAME, LOC FROM EMP, DEPT  WHERE (EMP.DEPTNO=DEPT.DEPTNO) AND HIREDATE <'31-DEC-82' AND DEPT.LOC IN ('CHICAGO','NEW YORK');

99) DISPLAY EMPLOYEE NAME, JOB, DEPARTMENT, LOCATION FOR ALL WHO ARE WORKING AS MANAGER?

SQL>select ename, JOB, DNAME, LOCATION from EMP, DEPT where mgr is not Null;

100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS JONES? [AND ALSO DISPLAY THEIR MANAGER NAME]?

SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR AND E.ENAME='JONES';

101) Display name and salary of ford if his salary is equal to hisal of his Grade

a)  Select ename, sal, grade from EMP, salgrade where sal between losal and hisal  and ename ='FORD' AND HISAL=SAL;

102) Display employee name, job, depart name, manager name, his grade and make out an under department wise?

SQL>SELECT E.ENAME, E.JOB, DNAME, EMP.ENAME, GRADE FROM EMP,EMP E, SALGRADE, DEPT
WHERE EMP.SAL BETWEEN LOSAL AND HISAL AND EMP.EMPNO=E.MGR  AND EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME

103) List out all employees name,job,salary,grade and depart name for every one in the company  except 'CLERK'.Sort on salary display the highest salary?

SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE FROM EMP,SALGRADE,DEPT WHERE SAL BETWEEN LOSAL AND HISAL AND EMP.DEPTNO=DEPT.DEPTNO AND JOB
NOT IN('CLERK')ORDER BY SAL ASC;

104) Display the employee name,job and his manager.Display also employee who are without manager?

SQL>select e.ename,e.job,eMP.ename AS Manager from emp,emp e where emp.empno(+)=e.mgr

105) Find out the top 5 earners of company?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT COUNT(DISTINCT SAL) FROM  EMP A WHERE A.SAL>=E.SAL)ORDER BY SAL DESC;

106) Display name of those employee who are getting the highest salary?

SQL>select ename from emp where sal=(select max(sal) from emp);

107) Display those employee whose salary is equal to average of maximum and minimum?

SQL>select ename from emp where sal=(select max(sal)+min(sal)/2 from emp);

108) Select count of employee in each department  where count greater than 3?

SQL>select count(*) from emp group by deptno having count(deptno)>3

109) Display dname where at least 3 are working and display only department name?

SQL>select distinct d.dname from dept d,emp e where d.deptno=e.deptno and 3> any (select count(deptno) from emp group by deptno)

110) Display name of those managers name whose salary is more than average salary of his company?

SQL>SELECT E.ENAME,EMP.ENAME FROM EMP,EMP E
WHERE EMP.EMPNO=E.MGR AND E.SAL>(SELECT AVG(SAL) FROM EMP);

111)Display those managers name whose salary is more than average salary of his employee?

SQL>SELECT DISTINCT EMP.ENAME FROM EMP,EMP E WHERE  E.SAL <(SELECT AVG(EMP.SAL) FROM EMP
WHERE EMP.EMPNO=E.MGR GROUP BY EMP.ENAME) AND EMP.EMPNO=E.MGR;

112) Display employee name,sal,comm and net pay for those employee whose net pay is greter than or equal to any other employee salary of the company?

SQL>select ename,sal,comm,sal+nvl(comm,0) as NetPay from emp where sal+nvl(comm,0) >any (select sal from emp)

113) Display all employees names with total sal of company with each employee name?

SQL>SELECT ENAME,(SELECT SUM(SAL)  FROM EMP) FROM EMP;

114) Find out last 5(least)earners of the company.?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE
5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL<=E.SAL) ORDER BY SAL DESC;

115) Find out the number of employees whose salary is greater than their manager salary?

SQL>SELECT E.ENAME FROM EMP ,EMP E WHERE EMP.EMPNO=E.MGR AND EMP.SAL<E.SAL;

116) Display those department where no employee working?

SQL>select dname from emp,dept where emp.deptno not in(emp.deptno)

117) Display those employee whose salary is ODD value?

SQL>select * from emp where sal<0;

118) Display those employee whose salary contains alleast 3 digits?

SQL>select * from emp where length(sal)>=3;

119) Display those employee who joined in the company in the month of Dec?

SQL>select ename from emp where to_char(hiredate,'MON')='DEC';

120) Display those employees whose name contains "A"?

SQL>select ename from emp where instr(ename,'A')>0;
                          or
SQL>select ename from emp where ename like('%A%');

121) Display those employee whose deptno is available in salary?

SQL>select emp.ename from emp, emp e where emp.sal=e.deptno;

122) Display those employee whose first 2 characters from hiredate -last 2 characters of salary?


SQL>select ename,SUBSTR(hiredate,1,2)||ENAME||substr(sal,-2,2) from emp

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I'm Ethan Mariano a software engineer by profession and reader/writter by passion.I have good understanding and knowledge of AngularJS, Database, javascript, web development, digital marketing and exploring other technologies related to Software development.

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