Program to calculate the volume of the sphere
A sphere is a perfectly round geometrical object
in 3-dimensional space. It is the set of all the points located a particular
distance away from a particular point called center. It is perfectly
symmetrical and has no edges or vertices.
Formula
Volume= (4/3)*pie*r3
Algorithm
- Define
the radius of the sphere
- Define
the pie and assign (22/7)
- Calculate
the volume of the sphere as (4/3)*pie*r3
- Assign
the volume of the sphere to volume_of_sphere
- Print
the volume of the sphere.
Complexity
O(1)
Solution
C Program
#include <stdio.h>
int main()
{
int radius=48;
float pie=3.14285714286;
double volume=(4.0/3.0)*pie*(radius*radius*radius);
printf("Volume of the sphere=%f",volume);
}
Output:
Volume of the
sphere=463433.132812
PHP Program
<?php
$radius=48;
$pie=3.14285714286;
$volume=(4/3)*$pie*($radius*$radius*$radius);
echo "Volume of the Sphere=";
echo $volume;
?>
Output:
Volume of the
Sphere=463433.14285756
Java Program
public class sphere{
public static void main(String args[])
{
int radius=48;
double pie=3.14285714286;
double volume=(4.0/3.0)*pie*(radius*radius*radius);
System.out.println("Volume of the sphere="+volume);
}
}
Output:
Volume of the
sphere=463433.14285756415
C# Program
using System;
public class Program
{
public static void Main()
{
int radius=48;
double pie=3.14285714286;
double volume=(4.0/3.0)*pie*(radius*radius*radius);
Console.WriteLine("Volume of sphere="+volume);
}
}
Output:
Volume of
sphere=463433.142857564
Python Program
radius=48
pie=3.14285714286
volume=(4.0/3.0)*pie*(radius*radius*radius)
print("volume of the sphere="+str(volume))
Output:
volume of the
sphere=463433.14285756415
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